2[k-(2k+10)+5]=2(k+5)

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Solution for 2[k-(2k+10)+5]=2(k+5) equation:


Simplifying
2[k + -1(2k + 10) + 5] = 2(k + 5)

Reorder the terms:
2[k + -1(10 + 2k) + 5] = 2(k + 5)
2[k + (10 * -1 + 2k * -1) + 5] = 2(k + 5)
2[k + (-10 + -2k) + 5] = 2(k + 5)

Reorder the terms:
2[-10 + 5 + k + -2k] = 2(k + 5)

Combine like terms: -10 + 5 = -5
2[-5 + k + -2k] = 2(k + 5)

Combine like terms: k + -2k = -1k
2[-5 + -1k] = 2(k + 5)
[-5 * 2 + -1k * 2] = 2(k + 5)
[-10 + -2k] = 2(k + 5)

Reorder the terms:
-10 + -2k = 2(5 + k)
-10 + -2k = (5 * 2 + k * 2)
-10 + -2k = (10 + 2k)

Solving
-10 + -2k = 10 + 2k

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '-2k' to each side of the equation.
-10 + -2k + -2k = 10 + 2k + -2k

Combine like terms: -2k + -2k = -4k
-10 + -4k = 10 + 2k + -2k

Combine like terms: 2k + -2k = 0
-10 + -4k = 10 + 0
-10 + -4k = 10

Add '10' to each side of the equation.
-10 + 10 + -4k = 10 + 10

Combine like terms: -10 + 10 = 0
0 + -4k = 10 + 10
-4k = 10 + 10

Combine like terms: 10 + 10 = 20
-4k = 20

Divide each side by '-4'.
k = -5

Simplifying
k = -5

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